![]() ![]() Does anyone know how I can amend my query, so that it searches both location and CRS and TIPLOC, LIKE on location, but exact match only on CRS and TIPLOC? if(isset($_REQUEST))). The above only displays the CRS result (exact match) and doesn't provide any suggestions for location, only shows CRS. Now i've only tried it with CRS so far, and ive done the following query: $sql = "SELECT location FROM location_data WHERE location OR CRS LIKE ? LIMIT 10" I would like to display results like the following: Select location FROM location_data WHERE location(textbox) is LIKE ?(what the person typed in) OR CRS is LIKE ? or TIPLOC is LIKE ? There are 3 different columns in a database table, one called location, one called CRS and one called tiploc. Example: SELECT t1.Notes, t2.Name FROM Table1 t1, Table2 t2 WHERE t1.Notes LIKE 't2. The issue I am having is with this query here: $sql = "SELECT location FROM location_data WHERE location LIKE ? LIMIT 10" I stumbled into a delicate SQL problem when I needed to use a value from a field inside a LIKE. I have a dynamically updating AJAX search form which shows location data from database. Would I need to put a parentID column in the database table and give an ID for each set of options? for example, Bracelet would have Silver, Gold and Silver Plate.I've had a look around Stackoverflow and can't seem to find what I am looking for. I have a dynamic dropdown tutorial which states that a parents and child lists would be needed, but seeing as I am only having one dropdown box, I think the child list would not be necessary. The third problem I have is I do not quite understand how the dropdown would only show the Colour, Size and Price options for the product of that product page. I have read on forums that the use of variables would do this for meīut am unsure as to how I would implement them into dropdown on the product page. The second problem I have is that I would like the selected data from theĭropdown to be transported to the next page which will be the Review Cart I am unsure how this is done in PHP MySQL. I am sure this is possible because I have done this ![]() I want to show all three one after the other in ![]() MySQL provides two wildcard characters for. The first problem I have is the DW insert list/menu feature only allows me to show one column of data. In this syntax, if the expression matches the pattern, the LIKE operator returns 1. I have been able to select whatĭynamic data I would like to show by use of a recordset I have already setup The Like operator uses Wildcards to extract the records matching the specified pattern. Page using the DW insert List/Menu feature. The MySQL LIKE Operator is used to perform a wild search on tables. I am using Dreamweaver MX 2004 and have already setup the dropdown on the Unfortunately, we don't have the teacher ID column in the students table. For this, we need to combine the information from the tables students and teachers. Installed, configured and fully operational. Example 1: SQL JOIN by Two Columns In our first example, we want to know the education level of the teacher for each student. I have the database setup and running with Apache, PHP and MySQL all I want this dropdown box to show data from three different columns in a MySQL database table. I have a product page which has static information on it. allows your users to search the content field for anything they like. ![]() select column1, column2, column3 where column1 like '05' from mytable How to give Multiple Like Conditions Below example says, general syntax of usage of multiple like conditions in Where clause. Query multiple columns in a mySQL database using PHP to issue the mySQL commands. Website but as I am a PHP MySQL newbie, I have come accross a few problems. Below is the simple SQL to give Like condition in Where clause. I am currently in the process of setting up a e-commerce suite on a client ![]()
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